document.write( "Question 206743: On the first day Juanita receives 1 dollar. On each succeeding day, she receives 1 dollar more than the total received in all preceding days. On which day will she first receive an amount greater than one hundred dollars?\r
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document.write( "(A) 6th day (B) 7th day (C) 8th day (D) 9th day (E) 10th day \n" );
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Algebra.Com's Answer #156279 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! ): On the first day Juanita receives 1 dollar. On each succeeding day, she receives 1 dollar more than the total received in all preceding days. On which day will she first receive an amount greater than one hundred dollars? \n" ); document.write( "------- \n" ); document.write( "1st day 1 = 2^0 \n" ); document.write( "2nd day 2 = 2*1 \n" ); document.write( "3rd day 4 = 2^2 \n" ); document.write( "... \n" ); document.write( "nth day 2^(n-1) \n" ); document.write( "---------------------- \n" ); document.write( "You want to know what the smallest n is that will produce 2^(n-1)> 100 \n" ); document.write( "------------- \n" ); document.write( "Equation: 2^(n-1) = 100 \n" ); document.write( "Take the log of both sides to get: \n" ); document.write( "(n-1)log(2) = log(100 \n" ); document.write( "(n-1) = log(100)/log(2) \n" ); document.write( "n-1 = 2/log(2) = 6.644 \n" ); document.write( "n = 7.644 \n" ); document.write( "--- \n" ); document.write( "She will receive more than 100 on the 8th day and beyond. \n" ); document.write( "=========================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "===========================\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "(A) 6th day (B) 7th day (C) 8th day (D) 9th day (E) 10th day \n" ); document.write( " \n" ); document.write( " |