document.write( "Question 28699: The relationship between the air temperatur t (in degrees Fahrenheit) and the altitude h ( in feet above sea level) is approcimately linear. At 1000 ft, the temperature is 60*. At 5000ft the temperature is 42*. Express t in therms of h. Use proper or improper fractions or exact decimals only no decimal approcimations. \n" ); document.write( "

Algebra.Com's Answer #15626 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
If it's a linear relation then
\n" ); document.write( "t = mh +k where m is the slope and t = k when h = 0
\n" ); document.write( " $\"%28t+-+60%29+%2F+%28h+-+1000%29+=+%2842+-+60%29+%2F+%285000+-+1000%29\"$
\n" ); document.write( "this is the same as
\n" ); document.write( "

\n" ); document.write( " $\"%28t+-+60%29+%2F+%28h+-+1000%29+=+-18+%2F+4000%29\"$
\n" ); document.write( "multiply both sides by (h - 1000)
\n" ); document.write( " $\"+t+-+60+=+-%284.5+%2A+10%5E-3%29%2Ah+%2B+4.5\"$
\n" ); document.write( " $\"+t+=+-%284.5+%2A+10%5E-3%29%2Ah+%2B+64.5\"$
\n" ); document.write( "check
\n" ); document.write( "when h = 1000
\n" ); document.write( " $\"+t+=+-%284.5+%2A+10%5E-3%29%2A10%5E3+%2B+64.5\"$
\n" ); document.write( " $\"t+=+-4.5+%2B+64.5\"$
\n" ); document.write( " $\"t+=+60\"$
\n" ); document.write( "when h = 5000
\n" ); document.write( " $\"+t+=+-%284.5+%2A+10%5E-3%29%2A5%2A10%5E3+%2B+64.5\"$
\n" ); document.write( " $\"+t+=+-%285+%2A+4.5%29+%2B+64.5\"$
\n" ); document.write( " $\"+t+=+-22.5+%2B+64.5\"$
\n" ); document.write( " $\"+t+=+42\"$
\n" ); document.write( "OK \n" ); document.write( "

\n" );