document.write( "Question 206710: Solve the problem.\r
\n" ); document.write( "\n" ); document.write( "By holding a ruler 3 feet in front of her eyes as illustrated in the diagram, Carla sees that the top and bottom points of a vertical cliff face line up with marks separated by 4\" on the ruler. According to the map, Carla is about a half mile from the cliff. What is the approximate height of the cliff rounded to the nearest foot? Recall that a mile is 5280 feet.\r
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\n" ); document.write( "\n" ); document.write( "(I dont know if this problem is solvable without the pictue, but it is basically Carla viewing the mountain from a particulat distance)
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Algebra.Com's Answer #156253 by vleith(2983)\"\" \"About 
You can put this solution on YOUR website!
Use the properties of similar triangles. The triangle formed by her arm, the ruler and the hypotenuse AND the triangle formed by 1/2 mile, the cliff and that hypotenuse are similar.\r
\n" ); document.write( "\n" ); document.write( "So
\n" ); document.write( "\"armLength%2FhalfMile+=+4inch%2FcliffHeight\"
\n" ); document.write( "convert everything to feet
\n" ); document.write( "halfMile = 5280/2 = 2640
\n" ); document.write( "4inches = 1/3 foot
\n" ); document.write( "\"3%2F2640+=+%281%2F3%29%2FCliff\"
\n" ); document.write( "\"Cliff+=+%281%2F3%29%2A2640%2F3\"
\n" ); document.write( "\"Cliff+=+293+feet\"
\n" ); document.write( "Note that this is a very rough estimate. No way Carla has a three foot arm. No way even the littlest error in the 4inches doesnt translate to a huge error on the size of the cliff. But, is better than a wild guess
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