document.write( "Question 206702This question is from textbook intermediate algebra
\n" ); document.write( ": solve and graph the solution set:
\n" ); document.write( "((2x-1)(x+3))/(x-4) ≤0 \n" ); document.write( "
Algebra.Com's Answer #156237 by stanbon(75887)\"\" \"About 
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solve and graph the solution set:
\n" ); document.write( "((2x-1)(x+3))/(x-4) ≤0
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\n" ); document.write( "Draw a number line and mark x = 1/2, -3, and 4
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\n" ); document.write( "x = 1/2 and x = -3 are part of the solution set. x=4 is not allowed.
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\n" ); document.write( "You want to know when the left side is negative so check the sign
\n" ); document.write( "of the left side with check values in the intervals of the number line.
\n" ); document.write( "Check x = -5
\n" ); document.write( "The left signs are: -*-/- < 0 so solutions in (-inf,-3)
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\n" ); document.write( "Check x = 0
\n" ); document.write( "The left signs are: -*+/- > 0 so NO solutions in (-3,1/2)
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\n" ); document.write( "Check x = 2
\n" ); document.write( "The left signs are +*+/- < 0 so solutions in [1/2,4)
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\n" ); document.write( "Check x = 5
\n" ); document.write( "The left signs are: +*+/+ > 0 so NO solutions in (4,+inf)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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