document.write( "Question 28692: How much pure alcohol must a nurse add to 8cc of a 70% solution to strengthen it to a 90% solution? Just need to know if this is right and if not what is right. \r
\n" ); document.write( "\n" ); document.write( ".90(8)+ 0(x) = .70(x+8)\r
\n" ); document.write( "\n" ); document.write( "7.2 = .70x+5.6\r
\n" ); document.write( "\n" ); document.write( "1.6 = 70x\r
\n" ); document.write( "\n" ); document.write( "2.29c = x \n" ); document.write( "
Algebra.Com's Answer #15621 by venugopalramana(3286)\"\" \"About 
You can put this solution on YOUR website!
How much pure alcohol must a nurse add to 8cc of a 70% solution to strengthen it to a 90% solution? Just need to know if this is right and if not what is right.
\n" ); document.write( ".90(8)+ 0(x) = .70(x+8)....NO ...FIRST WRITE DOWN WHAT IS X?I THINK X IS QTY.OF
\n" ); document.write( "PURE ALCOHOL TO BE ADDED TO 8 CC OF 70% ALCOHOL TO GET X+8 CC OF 90% SOLUTION.SO THE EQN. SHOULD BE X*100/100+8*70/100=(X+8)*90/100
\n" ); document.write( "7.2 = .70x+5.6.....X+5.6=0.9(X+8)
\n" ); document.write( "1.6 = 70x.......X-0.9X=7.2-5.6=1.6
\n" ); document.write( "2.29c = x.......0.1X=1.6
\n" ); document.write( "..................OR X=1.6/0.1=16 CC.
\n" ); document.write( "SEE THE FOLLOWING EXAMPLE WHICH WILL HELP YOU TO GET AN INSIGHT INTO THESE PROBLEMS AND THE METHOD OF APPROACH TO SOLVE THEM
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\n" ); document.write( "answer 15572 by venugopalramana(1008) About Me on 2006-02-26 07:15:31 (Show Source):\r
\n" ); document.write( "\n" ); document.write( "PLEASE HELP ASAP: Ziggy's famous yogurt blends regular yogurt that is 3% fat with its no fat yogurt to obtain low fat yogurt that is 1% fat. How many pounds of regular and how many pounds of non-fat yogurt should be mixed to obtain 60 pounds of lowfat yogurt.
\n" ); document.write( "PLEASE HELP ASAP. thank you
\n" ); document.write( "THESE ARE MATERIAL BALANCE PROBLEMS.THE PRINCIPLE IS TO APPLY
\n" ); document.write( "TOTAL OF ALL INPUTS =TOTAL OF ALL OUTPUTS..
\n" ); document.write( "THIS PRINCIPLE CAN BE APPLIED TO TOTAL MIXTURE AS A WHOLE AS WELL AS INDIVIDUAL COMPONENTS OF THE MIXTURE.LET US SEE THE APPLICATION USING YOUR PROBLEM.
\n" ); document.write( "HERE THE MIXTURE COMPRISES 2 INPUTS-REGULAR YOGURT (RY) & NO FAT YOGURT (NFY)
\n" ); document.write( "AND ONE OUT PUT-LOW FAT YOGURT (LFY).THE COMPONENT OF IMPORTANCE IN THE MIXTURE IS FAT CONTENT.SO WE TAKE 2 BALANCES HERE ..ONE FOR THE TOTAL MIXTURE AND ANOTHER FOR COMPONENT OF FAT IN THE MIXTURE.
\n" ); document.write( "I..TOTAL BALANCE...
\n" ); document.write( "INPUTS
\n" ); document.write( "1.QTY.OF.RY=X POUNDS
\n" ); document.write( "2.QTY OF NFY=Y POUNDS
\n" ); document.write( "OUT PUT
\n" ); document.write( "1.QTY.OF LFY=60 POUNDS
\n" ); document.write( "SO APPLYING
\n" ); document.write( "TOTAL OF ALL INPUTS =TOTAL OF ALL OUTPUTS.....WE GET
\n" ); document.write( "X+Y=60.............................I
\n" ); document.write( "II..COMPONENT BALANCE..HERE IT IS FAT .
\n" ); document.write( "INPUTS
\n" ); document.write( "1.QTY.OF FAT IN RY=X*3/100=3X/100 POUNDS
\n" ); document.write( "2.QTY OF FAT IN NFY=Y*0/100=0 POUNDS
\n" ); document.write( "OUT PUT
\n" ); document.write( "1.QTY.OF FAT IN LFY=60*1/100=60/100 POUNDS
\n" ); document.write( "SO APPLYING
\n" ); document.write( "TOTAL OF ALL INPUTS =TOTAL OF ALL OUTPUTS.....WE GET
\n" ); document.write( "3X/100 + 0=60/100.............................II
\n" ); document.write( "3X=60
\n" ); document.write( "X=20 POUNDS. OF REGULAR YOGURT
\n" ); document.write( "Y=60-20=40 POUNDS OF NO FAT YOGURT. \n" ); document.write( "
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