document.write( "Question 3204: X2 + y2 = 25 where Y =3\r
\n" ); document.write( "\n" ); document.write( "what is the answer? Please Please Please and how did you arrive at it.\r
\n" ); document.write( "\n" ); document.write( "9
\n" ); document.write( "5
\n" ); document.write( "16
\n" ); document.write( "4
\n" ); document.write( "Thank you so very much inadvance.
\n" ); document.write( "trica.
\n" ); document.write( "

Algebra.Com's Answer #1562 by Pieter(35)\"\" \"About 
You can put this solution on YOUR website!
2x + 2y = 25 and you know that y = 3
\n" ); document.write( "you simply put this 3 in the equation where y stands:\r
\n" ); document.write( "\n" ); document.write( "2x + 2*3 = 25
\n" ); document.write( "now bring everything that is not x to the other side:
\n" ); document.write( "2x = 25 - 6 = 19
\n" ); document.write( "so x = 19/2 = 9.5\r
\n" ); document.write( "\n" ); document.write( "is this what you meant?\r
\n" ); document.write( "\n" ); document.write( "Greets,
\n" ); document.write( "gurdebeke_pieter@hotmail.com for questions
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