document.write( "Question 206637: Chris and leslie drove at total of 503 miles in 12.8 hours. Christ drove the first part of the trip and averaged 45 miles per hour. Leslie drove the remainder of the trip and averaged 35 miles per hour. For what length of the time did Chris drive? \n" ); document.write( "
Algebra.Com's Answer #156178 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Chris and leslie drove at total of 503 miles in 12.8 hours. \n" ); document.write( "Christ drove the first part of the trip and averaged 45 miles per hour. \n" ); document.write( " Leslie drove the remainder of the trip and averaged 35 miles per hour. \n" ); document.write( "For what length of the time did Chris drive? \n" ); document.write( ": \n" ); document.write( "Let t = time that Chris drove \n" ); document.write( "then \n" ); document.write( "(12.8 - t) = time Leslie drove \n" ); document.write( ": \n" ); document.write( "Write distance equation: Dist = speed * time \n" ); document.write( ": \n" ); document.write( "C's drive dist + L's drive dist = 503 mi \n" ); document.write( "45t + 35(12.8 - t) = 503 \n" ); document.write( ": \n" ); document.write( "45t + 448 - 35t = 503 \n" ); document.write( ": \n" ); document.write( "45t - 35t = 503 - 448 \n" ); document.write( ": \n" ); document.write( "10t = 55 \n" ); document.write( "t = \n" ); document.write( "t = 5.5 hrs, drive time of Chris \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution \n" ); document.write( "12.8 - 5.5 = 7.3 hrs drive time of Leslie \n" ); document.write( "Find the distances \n" ); document.write( "45 * 5.5 = 247.5 mi \n" ); document.write( "35 * 7.3 = 255.5 \n" ); document.write( "------------------ \n" ); document.write( "total dist:503 mi; confirms our solution \n" ); document.write( " \n" ); document.write( " |