document.write( "Question 206584: Rick and Maura work together ans sew a quilt in 4 hrs. Working alone maura wiould need 6 hrs more than rick to sew the quilt. How long would it take each if they worked alone? \n" ); document.write( "
Algebra.Com's Answer #156158 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Rick and Maura work together ans sew a quilt in 4 hrs. \n" ); document.write( " Working alone Maura would need 6 hrs more than Rick to sew the quilt. \n" ); document.write( " How long would it take each if they worked alone? \n" ); document.write( ": \n" ); document.write( "Let t = time required by Rick alone \n" ); document.write( "then \n" ); document.write( "(t+6) = Maura alone \n" ); document.write( ": \n" ); document.write( "Let the completed quilt = 1 \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( "Multiply equation by t(t+6) to get rid of the denominators, results \n" ); document.write( ": \n" ); document.write( "4t + 4(t+6) = t(t+6) \n" ); document.write( ": \n" ); document.write( "4t + 4t + 24 = t^2 + 6t \n" ); document.write( ": \n" ); document.write( "8t + 24 = t^2 + 6t \n" ); document.write( ": \n" ); document.write( "Arrange as a quadratic on the right \n" ); document.write( "0 = t^2 + 6t - 8t - 24 \n" ); document.write( ": \n" ); document.write( "t^2 - 2t - 24 = 0 \n" ); document.write( "Factors to: \n" ); document.write( "(t-6)(t+4) = 0 \n" ); document.write( ": \n" ); document.write( "positive solution \n" ); document.write( "t = 6 hrs, is Rick's time alone \n" ); document.write( "and \n" ); document.write( "6 + 6 = 12 hrs Maura's time alone \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution in original equation \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |