document.write( "Question 206612: 1/3x+9 = x+1/x^2+3x + 1/3x^2+9x \n" ); document.write( "
Algebra.Com's Answer #156155 by mickclns(59)\"\" \"About 
You can put this solution on YOUR website!
\"1%2F3x%2B9+=+x%2B1%2Fx%5E2%2B3x+%2B+1%2F3x%5E2%2B9x\" is what you wrote. I think that when you changed your fractions from vertical to horizontal you forgot the parentheses, so I think this is what you meant (correct me if I'm wrong):
\n" ); document.write( "\"1%2F%283x%2B9%29+=+%28x%2B1%29%2F%28x%5E2%2B3x%29+%2B+1%2F%283x%5E2%2B9x%29\" Factor everything you can.
\n" ); document.write( "\"+1%2F%283%28x%2B3%29%29+=+%28x%2B1%29%2F%28x%28x%2B3%29%29+%2B+1%2F%283x%28x%2B3%29%29+\"
\n" ); document.write( "Get a (least) common denominator of all the fractions which is 3x(x+3) (why is that the LCD?)
\n" ); document.write( "\"+x%2F%283x%28x%2B3%29%29+=+3%28x%2B1%29%2F%283x%28x%2B3%29%29+%2B+1%2F%283x%28x%2B3%29%29+\" and multiply both sides by the LCD to get rid of fractions.
\n" ); document.write( "\"x+=+3x%2B3+%2B+1\" subtract 3x from both sides and combine like terms
\n" ); document.write( "\"-2x+=+4\"
\n" ); document.write( "\"x+=+-2\"
\n" ); document.write( " 
\n" ); document.write( "check answer in ORIGINAL
\n" ); document.write( " ?
\n" ); document.write( "\"1%2F3+=+%28-1%29%2F%284-6%29+%2B+1%2F%2812-18%29\" ?
\n" ); document.write( "\"1%2F3+=+1%2F2+-+1%2F6=%283-1%29%2F6=1%2F3\" Yes!
\n" ); document.write( " 
\n" ); document.write( " 
\n" ); document.write( "
\n" );