document.write( "Question 206019This question is from textbook Intermediate Algebra
\n" ); document.write( ": x^2 - 3x^1/2 - 10 = 0 \n" ); document.write( "
Algebra.Com's Answer #156131 by mickclns(59)\"\" \"About 
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\"+x%5E2+-+%283x%5E1%29+%2F+2+-+10+=+0+\" notation housekeeping
\n" ); document.write( "\"+x%5E2+-+%283%2F2%29x+-+10+=+0+\" multiply both sides by 2 to get rid of the fraction
\n" ); document.write( "\"+2x%5E2+-+3x+-+20+=+0+\"\r
\n" ); document.write( "\n" ); document.write( "There are various ways of factoring a quadratic (if it factors, which this does, because \"b%5E2-4%2Aa%2Ac+=+9+%2B+160+=+169+\" is a perfect square). I like this way:
\n" ); document.write( "\"+2x%5E2+-+3x+-+20+=+0+\" First multiply the coefficient of the \"+x%5E2+\" term, 2, by the constant term, -20, to get -40. Now you want to find two numbers that multiply to this number, -40, and that add to the coefficient of x, in this case -3. The two numbers are -8 and 5.
\n" ); document.write( "Now you put those two numbers into the blanks in \"+2x%5E2+%2B+_x++%2B+_x+-+20+\" (and it doesn't matter which number in which blank):
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\n" ); document.write( "Case 1: \"+2x%5E2+%2B+%28-8%29x++%2B+%285%29x+-+20+\". Now factor out whatever you can out of the first two terms and factor out whatever you can out of the last two terms:
\n" ); document.write( "\"2x%28x+-+4%29+%2B+5%28x+-+4%29\". Notice both terms have a factor of x-4 which you can factor out:
\n" ); document.write( "\"%282x+%2B+5%29+%28x-4%29\".
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\n" ); document.write( "Case 2: \"+2x%5E2+%2B+%285%29x++%2B+%28-8%29x+-+20+\". Now factor out whatever you can out of the first two terms and factor out whatever you can out of the last two terms:
\n" ); document.write( "\"x%282x+%2B5%29+%2B+-4%282x+%2B+5%29\". Again, both terms have a factor, 2x + 5 this time, which you can factor out:
\n" ); document.write( "\"%28x-4%29+%282x+%2B+5%29\".
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\n" ); document.write( "In both cases the factors are the same except in opposite order, which makes not a whit of difference.
\n" ); document.write( "It is a good idea to multiply out (FOIL) to make sure you have factored correctly
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\n" ); document.write( "Now we use the zero product property which says that if a product of a bunch of numbers is 0 then one of the numbers must be 0, which is what allows us to set each of the factors to 0.
\n" ); document.write( "\"%28x-4%29+%282x+%2B+5%29+=+0\" --> \"x-4+=+0\" or \"2x%2B5+=+0\", so \"x+=+4\" or \"x+=+-5%2F2\". \r
\n" ); document.write( "\n" ); document.write( "Now it's a good idea to check your answers to make sure they work, by plugging them in (one at a time) for x in the ORIGINAL equation (I will do one, you can do the other):
\n" ); document.write( "\"+%28-5%2F2%29%5E2+-+%283%28-5%2F2%29%5E1%29+%2F+2+-+10+=+0+\" ?
\n" ); document.write( "\"+25%2F4+%2B+15%2F4+-+10+=+0\"?
\n" ); document.write( "\"40%2F4+-+10+=+0\"?
\n" ); document.write( "\"0+=+0\" Yes!
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