document.write( "Question 205849: A plane reaches 1200 Km 1 hr earlier, if the speed of the plane is increased by 60km/hr from its initial speed. what is the initial speed of the plane? \n" ); document.write( "
Algebra.Com's Answer #156117 by AndrewRyan(3)\"\" \"About 
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(x+60) [(1200/x)-1] = 1200
\n" ); document.write( "1200 - x + (72000/x) - 60 = 1200
\n" ); document.write( "x(1200 - 60 - x + (72000/x) = 1200)
\n" ); document.write( "1140x - x^2 + 72000 = 1200x
\n" ); document.write( "-x^2 + 1140x - 1200x + 72000 = 0
\n" ); document.write( "-x^2 - 60x + 72000 = 0
\n" ); document.write( "x^2 + 60x - 72000 = 0
\n" ); document.write( "\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"1x%5E2%2B60x%2B-72000+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%2860%29%5E2-4%2A1%2A-72000=291600\".
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\n" ); document.write( " Discriminant d=291600 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-60%2B-sqrt%28+291600+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%2860%29%2Bsqrt%28+291600+%29%29%2F2%5C1+=+240\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%2860%29-sqrt%28+291600+%29%29%2F2%5C1+=+-300\"
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\n" ); document.write( " Quadratic expression \"1x%5E2%2B60x%2B-72000\" can be factored:
\n" ); document.write( " \"1x%5E2%2B60x%2B-72000+=+1%28x-240%29%2A%28x--300%29\"
\n" ); document.write( " Again, the answer is: 240, -300.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B60%2Ax%2B-72000+%29\"

\n" ); document.write( "\n" ); document.write( "(x - 240)(x + 300)
\n" ); document.write( "x = 240; x = -300 [-300 will be ignored because there is no negative speed]
\n" ); document.write( "x = 240\r
\n" ); document.write( "\n" ); document.write( "checking:
\n" ); document.write( "(240+60) [(1200/240)-1] = 1200
\n" ); document.write( "(300) (5 - 1) = 1200
\n" ); document.write( "(300) (4) = 1200
\n" ); document.write( "1200 = 1200
\n" ); document.write( "x = 240 is a solution
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