document.write( "Question 206289: an airplane flies between two cities 450 kilometers apart traveling with a wind of 45mph going and against the same wind when returning. the trip out takes one less hour than the return trip. what is the speed of the plane in still air? \n" ); document.write( "
Algebra.Com's Answer #156101 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! an airplane flies between two cities 450 kilometers apart traveling with a wind \n" ); document.write( " of 45 mph going and against the same wind when returning. \n" ); document.write( "the trip out takes one less hour than the return trip. \n" ); document.write( "what is the speed of the plane in still air? \n" ); document.write( ": \n" ); document.write( "Let s = plane speed in still air \n" ); document.write( "then \n" ); document.write( "(s+45) = speed with the wind \n" ); document.write( "and \n" ); document.write( "(s-45) = speed against the wind \n" ); document.write( "; \n" ); document.write( "Write a time equation: Time = \n" ); document.write( ": \n" ); document.write( "trip out + 1 hour = trip back \n" ); document.write( " \n" ); document.write( "Multiply equation by (s+45)(s-45), results \n" ); document.write( ": \n" ); document.write( "450(s-45) + (s+45)(s-45)*1 = 450(s+45) \n" ); document.write( ": \n" ); document.write( "450s - 20250 + s^2 - 2025 = 450s + 20250 \n" ); document.write( ": \n" ); document.write( "Arrange on the left \n" ); document.write( "s^2 + 450s - 450s - 2025 - 20250 - 20250 = 0 \n" ); document.write( ": \n" ); document.write( "s^2 - 42525 = 0 \n" ); document.write( "; \n" ); document.write( "s^2 = 42525 \n" ); document.write( "s = \n" ); document.write( "s = 206.2 speed in still air \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution by finding the times of each trip \n" ); document.write( "450/251.2 = 1.79 hrs \n" ); document.write( "450/161.2 = 2.79 hrs \n" ); document.write( "differs by 1 hr \n" ); document.write( " |