document.write( "Question 206555: How do you find the standard form of the equation of a circle, with a center (3,-1) through the point (-5,1)? \n" ); document.write( "
Algebra.Com's Answer #156096 by Alan3354(69443) You can put this solution on YOUR website! How do you find the standard form of the equation of a circle, with a center (3,-1) through the point (-5,1)? \n" ); document.write( "-------------- \n" ); document.write( "Find the distance to the point, that's the radius. \n" ); document.write( "r^2 = diffy^2 + diffx^2 \n" ); document.write( "r^2 = 2^2 + 8^2 \n" ); document.write( "r^2 = 68 \n" ); document.write( "------------ \n" ); document.write( "Then it's (x-h)^2 + (y-k)^2 = r^2 (h,k) is the center \n" ); document.write( "(x-3)^2 + (y+1)^2 = 68 \n" ); document.write( "---------------- \n" ); document.write( "It can be expanded and rearranged. \n" ); document.write( " |