document.write( "Question 206365: The dimensions of a garden are in whole numbers. If the length is reduced by 3 and the width reduced by 1 then the area is reduced by half. What were the dimensions and area of the original rectangle.\r
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document.write( "I know the answer but cannot find the math to get to it! \n" );
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Algebra.Com's Answer #156089 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! The dimensions of a garden are in whole numbers. \n" ); document.write( " If the length is reduced by 3 and the width reduced by 1 then the area is reduced by half. \n" ); document.write( "What were the dimensions and area of the original rectangle. \n" ); document.write( ": \n" ); document.write( "Let L = original length \n" ); document.write( "Let W = original width \n" ); document.write( "LW = original area \n" ); document.write( ": \n" ); document.write( "(L-3) = new length \n" ); document.write( "(W-1) = new width \n" ); document.write( "New area = (L-3)*(W-1) = (LW - L - 3W + 3) \n" ); document.write( ": \n" ); document.write( "Original area = twice new area \n" ); document.write( "LW = 2(LW - L - 3W + 3) \n" ); document.write( ": \n" ); document.write( "LW = 2LW - 2L - 6W + 6 \n" ); document.write( ": \n" ); document.write( "2LW - LW - 2L - 6W + 6 = 0 \n" ); document.write( ": \n" ); document.write( "LW - 2L = 6W - 6 \n" ); document.write( ": \n" ); document.write( "L(W - 2) = 6W - 6 \n" ); document.write( "L = \n" ); document.write( "Find a value for W that produces an integer value for L \n" ); document.write( "W = 3 \n" ); document.write( "L = \n" ); document.write( "L = 12 \n" ); document.write( ": \n" ); document.write( "original: 12 by 3 \n" ); document.write( "original area = 36 \n" ); document.write( ": \n" ); document.write( "Check solution \n" ); document.write( "New area: 9 * 2 = 18, half the original \n" ); document.write( " \n" ); document.write( " |