document.write( "Question 206365: The dimensions of a garden are in whole numbers. If the length is reduced by 3 and the width reduced by 1 then the area is reduced by half. What were the dimensions and area of the original rectangle.\r
\n" ); document.write( "\n" ); document.write( "I know the answer but cannot find the math to get to it!
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Algebra.Com's Answer #156089 by ankor@dixie-net.com(22740)\"\" \"About 
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The dimensions of a garden are in whole numbers.
\n" ); document.write( " If the length is reduced by 3 and the width reduced by 1 then the area is reduced by half.
\n" ); document.write( "What were the dimensions and area of the original rectangle.
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\n" ); document.write( "Let L = original length
\n" ); document.write( "Let W = original width
\n" ); document.write( "LW = original area
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\n" ); document.write( "(L-3) = new length
\n" ); document.write( "(W-1) = new width
\n" ); document.write( "New area = (L-3)*(W-1) = (LW - L - 3W + 3)
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\n" ); document.write( "Original area = twice new area
\n" ); document.write( "LW = 2(LW - L - 3W + 3)
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\n" ); document.write( "LW = 2LW - 2L - 6W + 6
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\n" ); document.write( "2LW - LW - 2L - 6W + 6 = 0
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\n" ); document.write( "LW - 2L = 6W - 6
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\n" ); document.write( "L(W - 2) = 6W - 6
\n" ); document.write( "L = \"%286W+-+6%29%2F%28W+-+2%29\"
\n" ); document.write( "Find a value for W that produces an integer value for L
\n" ); document.write( "W = 3
\n" ); document.write( "L = \"%286%283%29+-+6%29%2F%283+-+2%29\"
\n" ); document.write( "L = 12
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\n" ); document.write( "original: 12 by 3
\n" ); document.write( "original area = 36
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\n" ); document.write( "Check solution
\n" ); document.write( "New area: 9 * 2 = 18, half the original
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