document.write( "Question 28675: I hope I am asking this in the right section, but I need help with this problem. \r
\n" ); document.write( "\n" ); document.write( "A budget line shows all of the different combinations of goods a person can buy with a given budget, B. If a company has $500.00 to spend on 2 goods, \"a\" and \"b\" and \"a\" = $50.00 and \"b\" = $10.00, graph the budget line using the equation ax + by = B I tried this and got the following did I do this correctly?\r
\n" ); document.write( "\n" ); document.write( "ax + by = B
\n" ); document.write( "ax + by = 500
\n" ); document.write( "50x + 10y = 500
\n" ); document.write( "10y = 500 - 50x
\n" ); document.write( "y = 50-5x
\n" ); document.write( "I used -1, 0, 1 in my xy axis table
\n" ); document.write( "I came up with three ordered pairs of (-1,55) (0,50) (1,45)
\n" ); document.write( "

Algebra.Com's Answer #15606 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
You might use the inequality ax+by<=B.
\n" ); document.write( "The budget allows for $500 but certain
\n" ); document.write( "combinations of x and y might result
\n" ); document.write( "in expenses of < or = to $500.
\n" ); document.write( "Otherwise, your work looks good.
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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