document.write( "Question 206503: The length of a rectangle is 6 cm more than 1 1/2 times the width. The perimiter of the rectangle is 56 cm. Find the dimensions of the rectangle.Can someone show me the work too? \n" ); document.write( "
Algebra.Com's Answer #156045 by rfer(16322)\"\" \"About 
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width=x=8.8
\n" ); document.write( "length=1.5x+6=19.2
\n" ); document.write( "---------------
\n" ); document.write( "P=2L+2W
\n" ); document.write( "2(1.5x+6)+2x=56
\n" ); document.write( "3x+12+2x=56
\n" ); document.write( "subtract 12 from both sides.
\n" ); document.write( "5x=56-12
\n" ); document.write( "5x=44
\n" ); document.write( "x=8.8
\n" ); document.write( "--------------
\n" ); document.write( "P=2(8.8)+2(19.2)=56
\n" ); document.write( "
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