document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=206483>Question 206483</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the value of y for the given value of x by first substituting the value of x into the equation and solving for y.<BR>\n" );
document.write( " \r<BR>\n" );
document.write( "\n" );
document.write( "  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #156030 by </B><A HREF=/tutors/aboutme.mpl?userid=rfer><B>rfer(16322)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rfer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=156030\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 4x-3xy=16<BR>\n" );
document.write( "4(-2)-3(-2)(y)=16<BR>\n" );
document.write( "-8+6y=16<BR>\n" );
document.write( "subtract +8 from both sides to isolate the 6y<BR>\n" );
document.write( "-8+6y+8=16+8<BR>\n" );
document.write( "6y=24<BR>\n" );
document.write( "divide both sides by 6<BR>\n" );
document.write( "6y/6=24/6<BR>\n" );
document.write( "y=4<BR>\n" );
document.write( "--------------------<BR>\n" );
document.write( "When doing this problem watch the signs very closely. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );