document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=206464>Question 206464</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If f(x)=1-3x and g(x)=1/x2+1,find f(g(0)) and g(f(1)).\r<BR>\n" );
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document.write( "(by 1/x2+1 i mean 1 over x squared plus 1) PLEASE HELP!!! \r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #156016 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=156016\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If f(x)=1-3x and g(x)=1/(x^2+1),find f(g(0)) and g(f(1))<BR>\n" );
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document.write( "f[g(o)] = f[1] = 1-3 = -2<BR>\n" );
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document.write( "g[f(1)] = g[-2] = 1/(2^2+1) = 1/5<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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