Algebra.Com's Answer #155971 by Edwin McCravy(20056)  You can put this solution on YOUR website! According to Chebyshev's theorem, the proportion of values from a data set that is further than 2 standard deviations from the mean is at most-----? \n" );
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document.write( "All you have to do is learn Chebyshev's theorem in terms of k, then \r\n" );
document.write( "substitute 2 for k.\r\n" );
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document.write( "Here is Chebyshev's theorem in terms of k:\r\n" );
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document.write( "According to Chebyshev's theorem, the proportion of values \r\n" );
document.write( "from a data set that is further than standard deviations \r\n" );
document.write( "from the mean is at most .\r\n" );
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document.write( "Then when you plug in 2 for k, you get:\r\n" );
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document.write( "According to Chebyshev's theorem, the proportion of values \r\n" );
document.write( "from a data set that is further than standard deviations \r\n" );
document.write( "from the mean is at most .\r\n" );
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document.write( "or writing for ,\r\n" );
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document.write( "According to Chebyshev's theorem, the proportion of values \r\n" );
document.write( "from a data set that is further than standard deviations \r\n" );
document.write( "from the mean is at most .\r\n" );
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document.write( "Or if you prefer a decimal answer:\r\n" );
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document.write( "According to Chebyshev's theorem, the proportion of values \r\n" );
document.write( "from a data set that is further than standard deviations \r\n" );
document.write( "from the mean is at most .\r\n" );
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document.write( "Or if you prefer a percent answer:\r\n" );
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document.write( "According to Chebyshev's theorem, the proportion of values \r\n" );
document.write( "from a data set that is further than standard deviations \r\n" );
document.write( "from the mean is at most %.\r\n" );
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document.write( "Edwin \n" );
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