document.write( "Question 206256: two cars start moving from the same point. One travels south at 100 km/hr and the other travels west at 50 km/hr. How far apart are they two hours later? \n" ); document.write( "
Algebra.Com's Answer #155949 by MathTherapy(10552)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Since the southbound car is traveling at 100 km/hr, then in 2 hours it would've traveled 200 (2 * 100) km\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Since the westbound car is traveling at 50 km/hr, then in 2 hours it would've traveled 100 (2 * 50) km\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "If a figure is drawn, it'll be seen that the scenario has formed a right triangle, with the legs being 100 km and 200 km, thus leaving the hypotenuse as the distance betwen the 2 vehicles after 2 hours.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Using the Pythagorean formula, \"c%5E2+=+a%5E2+%2Bb%5E2\", to find this hypotenuse, we \r
\n" ); document.write( "\n" ); document.write( "get: \"c%5E2+=+100%5E2+%2B+200%5E2\" ------> \"c%5E2+=+10000+%2B+40000\"\r
\n" ); document.write( "\n" ); document.write( "\"c%5E2+=+50000\" -----> \"c++=++sqrt%2850000%29\"\r
\n" ); document.write( "\n" ); document.write( "c = 223.6068\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Therefore, 2 hours after starting out from the same point, the 2 cars are \"highlight_green%28223.6068%29\" km from each other.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );