document.write( "Question 28619: The sum of Rex's age and his son, Rodney's age is 50. Five years ago Rex was three times as old as Rodney. What are their ages now?
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Algebra.Com's Answer #15591 by Paul(988)\"\" \"About 
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Rex's age = x
\n" ); document.write( "Rodney = y\r
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\n" ); document.write( "\n" ); document.write( "x+y=50
\n" ); document.write( "y=50-x (sub)\r
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\n" ); document.write( "\n" ); document.write( "FIve years ago rex's age = x-5
\n" ); document.write( "Five years ago son's age = y-5\r
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\n" ); document.write( "\n" ); document.write( "3(y-5)=x-5
\n" ); document.write( "3y-5=x-5
\n" ); document.write( "SUb
\n" ); document.write( "3(50-x-5)=x-5
\n" ); document.write( "135-3x=x-5
\n" ); document.write( "-4x=-140
\n" ); document.write( "x=35\r
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\n" ); document.write( "\n" ); document.write( "y=50-35
\n" ); document.write( "y=15\r
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\n" ); document.write( "\n" ); document.write( "Hence, Rex is 35 years old and his son is 15 years old.
\n" ); document.write( "PAul.
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