document.write( "Question 28596: how to solve x + 2y = - 1 and 2x - 3y = 12 \n" ); document.write( "
Algebra.Com's Answer #15590 by sdmmadam@yahoo.com(530)\"\" \"About 
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how to solve x + 2y = - 1 and 2x - 3y = 12\r
\n" ); document.write( "\n" ); document.write( "x + 2y = - 1 ----(1)This gives x =(-1-2y)----(*)(adding -2y to both the sides)
\n" ); document.write( "Putting (*) in 2x - 3y = 12 ----(2) we get
\n" ); document.write( "2(-1-2y)-3y = 12
\n" ); document.write( "-2-4y-3y = 12
\n" ); document.write( "-4y-3y = 2+12 (adding 2 to both the sides)
\n" ); document.write( "-7y =14
\n" ); document.write( "y = -14/7 = -2
\n" ); document.write( "Putting y = -2 in (*),
\n" ); document.write( "x=(-1-2y)= -1-2X(-2) = -1+4 = 3
\n" ); document.write( "Answer: x=3 and y = -2
\n" ); document.write( "Verification: x=3 and y = -2 in 2x - 3y = 12 ----(2)
\n" ); document.write( "LHS= 2x - 3y = 2X3-3X(-2) = 6+6= 12=RHS
\n" ); document.write( "Therefore our values are correct.
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