document.write( "Question 206307This question is from textbook New Syllabus Mathematics D
\n" ); document.write( ": Kindly, help me solve this question.
\n" ); document.write( "There are 38 twenty cent coins, x ten cent coins and (2x-15)fifty cent coins in a box. A coin is selected at random and the probability that it is fifty cent coins is 1/8. Find the value of x. Hence, find the probability that the selected coin is a
\n" ); document.write( "(a) Twenty cent coin,
\n" ); document.write( "(b) Ten cent coin.
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Algebra.Com's Answer #155876 by mickclns(59) $\"\"$ $\"About$

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There are 38 + x + 2x-15 = 3x + 23 total coins and 1/8 of them are 50c coins
\n" ); document.write( "so (1/8)(3x+23) = 2x-15, which we are told is the number of 50c coins
\n" ); document.write( "Multiplying both sides of the above eqn by 8, we get:
\n" ); document.write( "3x +23 = 16x - 120 Subtracting 3x and adding 120 to both sides, we get:
\n" ); document.write( "143 = 13x Dividing both sides by 13, we have x = 11. So,
\n" ); document.write( "There are 38 twenties, 11 tens, 7 fifties and 56 total coins
\n" ); document.write( "a) p(twenty) = 38 / 56 = 19 / 28 and
\n" ); document.write( "b) p(ten) = 11/56 \n" ); document.write( "

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