document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=206253>Question 206253</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A small area in front of a building is triangular in shape. The perimeter of the triangle is 49 meters. The second side is one-fourth of the first side in length.  The third side is 4 meters more than the first side. Fing the length in meters of each side of the triangular region. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #155873 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=155873\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x+.25x+x+4=49<BR>\n" );
document.write( "2.25x=49-4<BR>\n" );
document.write( "2.25x=45<BR>\n" );
document.write( "x=45/2.25<BR>\n" );
document.write( "x=20 meters is the first side.<BR>\n" );
document.write( ".25*20=5 meters for the second side.<BR>\n" );
document.write( "20+4=24 meters for the third side.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "20+5+24=49<BR>\n" );
document.write( "49=49 <BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );