document.write( "Question 206306: Hi everyone, Im stumped on this one...\r
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document.write( "Find the vertex and intercepts of the function f(x) = x^(2) + x-2
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document.write( "A) Vertex:(0,2) ; Intercepts: (-2,0), (1,0), (0,-2)
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document.write( "B) Vertex: (- 1/2, - 9/4) ; Intercepts: (-2,0), (1, 0), (0,-2)
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document.write( "C) Vertex: (- 1/2, 9/4) ; Intercepts: (-2,0), (1,0), (0,-2)
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document.write( "D) Vertex: (-1, -18) ; Intercepts: (-2,0), (1,0), (0,2)
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document.write( " Thanks!! \n" );
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Algebra.Com's Answer #155872 by scott8148(6628)![]() ![]() You can put this solution on YOUR website! y-intercept (when x=0) is -2 ___ this eliminates answer D\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the vertex lies on the axis of symmetry ___ x = -b / (2a) = -1 / 2 ___ this eliminates answer A\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "substituting to find y ___ f(-1/2) = (-1/2)^2 + (-1/2) - 2 = -9/4 ___ answer B is correct \n" ); document.write( " |