document.write( "Question 28587: how do i simplify equations and clear this of fractons\r
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document.write( "x/2+y/3=7\r
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document.write( "x/4+2y/3=8 \n" );
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Algebra.Com's Answer #15587 by sdmmadam@yahoo.com(530)![]() ![]() ![]() You can put this solution on YOUR website! how do i simplify equations and clear this of fractons\r \n" ); document.write( "\n" ); document.write( "x/2+y/3=7 ----(1) \n" ); document.write( "x/4+2y/3=8 ----(2) \n" ); document.write( "In (1) the dr quantities on the LHS are 2 and 3. \n" ); document.write( "And the lcm of 2 and 3 is 6 \n" ); document.write( "Therefore multiply (1) throughout by 6 \n" ); document.write( "which gives 3x+2y = 42 ----(3) \n" ); document.write( "In (2) the dr quantities on the LHS are 4 and 3. \n" ); document.write( "And the lcm of 4 and 3 is 12 \n" ); document.write( "Therefore multiply (2) throughout by 12 \n" ); document.write( "which gives 3x+8y = 96 ----(4) \n" ); document.write( "Observe that the coefficients of x in both (3) and (4) are equal \n" ); document.write( "Therefore (3) - (4) should get rid of the x variable. \n" ); document.write( "(3) - (4) implies \n" ); document.write( "(3x-3x)+(2y-8y)= (42-96) \n" ); document.write( "0-6y = -54 \n" ); document.write( "-6y = -54 \n" ); document.write( "Therefore y = (-54)/(-6) = +9 \n" ); document.write( "x = 9 in 3x+2y = 42 ----(3) \n" ); document.write( "gives 3x+(2X9)=42 \n" ); document.write( "3x+18 = 42 \n" ); document.write( "3x=42-18 \n" ); document.write( "3x=24 \n" ); document.write( "x=24/3 = 8 \n" ); document.write( "Answer: x=8 and y=9 \n" ); document.write( "Verification: Putting x=8 and y=9 in x/4+2y/3=8 ----(2) \n" ); document.write( "LHS = x/4+2y/3= 8/4+(2X9)/3 = 2+6 = 8 =RHS \n" ); document.write( "Therefore our values are correct \n" ); document.write( " |