document.write( "Question 206285: A chemist has two solutions of H2SO4 one has 40% concentrate and the other has a 25% concentrate. Eash solution mustbe mixed to obtain 60 liters of a 30% solution? \n" ); document.write( "
Algebra.Com's Answer #155850 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A chemist has two solutions of H2SO4 one has 40% concentrate and the other has a 25% concentrate. \n" ); document.write( " Each solution must be mixed to obtain 60 liters of a 30% solution? \n" ); document.write( ": \n" ); document.write( "Let x = amt of 40% solution \n" ); document.write( "then \n" ); document.write( "(60-x) = amt of 25% solution \n" ); document.write( ": \n" ); document.write( "A simple mixture equation: \n" ); document.write( ".40x + .25(60-x) = .30(60) \n" ); document.write( ": \n" ); document.write( ".40x + 15 - .25x = 18 \n" ); document.write( ": \n" ); document.write( ".40x - .25x = 18 - 15 \n" ); document.write( ": \n" ); document.write( ".15x = 3 \n" ); document.write( "x = \n" ); document.write( "x = 20 liters of 40% solution \n" ); document.write( "and \n" ); document.write( "60 - 20 = 40 liters of 25% solution \n" ); document.write( "; \n" ); document.write( ": \n" ); document.write( "Check: \n" ); document.write( ".4(20) + .25(40) = .3(60) \n" ); document.write( "8 + 10 = 18 \n" ); document.write( " \n" ); document.write( " |