document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=206272>Question 206272</A>: <I><SPAN STYLE=\"word-break: break-all;\"> -3/2x + 11/4=-31/4\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #155838 by </B><A HREF=/tutors/aboutme.mpl?userid=profemmanuel2q@yahoo.com><B>profemmanuel2q@yahoo.com(15)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=profemmanuel2q@yahoo.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=155838\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -3/2x + 11/4=-31/4<BR>\n" );
document.write( "-3/2x = -31/4 - 11/4 ( Solve -31/4 - 11/4 by finding the LCM)So you will get<BR>\n" );
document.write( "-3/2x = -42/4 ( You just cross multiply)<BR>\n" );
document.write( "2x x -42 = -3 x 4<BR>\n" );
document.write( "-84x = -12 ( Divide both sides by - 84<BR>\n" );
document.write( "-84x/-84 = -12/-84 ( Just conceal do the cancealation<BR>\n" );
document.write( "So you have x = 1/7 </SPAN>\n" );
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