document.write( "Question 206259: log3(3x+6)-log3(x-6)=2 \n" ); document.write( "

Algebra.Com's Answer #155829 by nerdybill(7384) $\"\"$ $\"About$

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Applying log rules:
\n" ); document.write( "log3(3x+6)-log3(x-6)=2
\n" ); document.write( "log3[(3x+6)/(x-6)]=2
\n" ); document.write( "(3x+6)/(x-6) = 3^2
\n" ); document.write( "(3x+6)/(x-6) = 9
\n" ); document.write( "(3x+6) = 9(x-6)
\n" ); document.write( "3x+6 = 9x-54
\n" ); document.write( "6 = 6x-54
\n" ); document.write( "60 = 6x
\n" ); document.write( "10 = x\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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