document.write( "Question 206259: log3(3x+6)-log3(x-6)=2 \n" ); document.write( "

Algebra.Com's Answer #155828 by Marth(57) $\"\"$ $\"About$

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Remember that $\"log%28a%29-log%28b%29=log%28a%2Fb%29\"$
\n" ); document.write( "So given $\"log3%283x%2B6%29-log3%28x-6%29=2\"$
\n" ); document.write( "Simplify into $\"log3%28%283x%2B6%29%2F%28x-6%29%29=2\"$
\n" ); document.write( " $\"2=log3%289%29\"$
\n" ); document.write( "So, $\"log3%28%283x%2B6%29%2F%28x-6%29%29=log3%289%29\"$
\n" ); document.write( "Now you can remove the logarithms on both sides.
\n" ); document.write( " $\"%28%283x%2B6%29%2F%28x-6%29%29=9\"$
\n" ); document.write( " $\"3x%2B6=9%28x-6%29\"$
\n" ); document.write( " $\"3x%2B6=9x-54\"$
\n" ); document.write( " $\"60=6x\"$
\n" ); document.write( " $\"x=10\"$ \n" ); document.write( "

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