document.write( "Question 205930: 2.)The denominator of a fraction is 4 less than the numerator. If the denominator is doubled and the numerator is increased by 6, the sum of the original fraction and the new one is 3. Find the original fraction. \n" ); document.write( "
Algebra.Com's Answer #155806 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! The denominator of a fraction is 4 less than the numerator. \n" ); document.write( "d = n - 4 \n" ); document.write( ": \n" ); document.write( " If the denominator is doubled and the numerator is increased by 6, the sum of \n" ); document.write( "the original fraction and the new one is 3. \n" ); document.write( " \n" ); document.write( "Multiply equation by 2d, results: \n" ); document.write( "(n + 6) + 2n = 3(2d) \n" ); document.write( ": \n" ); document.write( "3n + 6 = 6d \n" ); document.write( "Replace d with (n-4) \n" ); document.write( "3n + 6 = 6(n-4) \n" ); document.write( ": \n" ); document.write( "3n + 6 = 6n - 24 \n" ); document.write( ": \n" ); document.write( "6 + 24 = 6n - 3n \n" ); document.write( ": \n" ); document.write( "30 = 3n \n" ); document.write( "n = \n" ); document.write( "n = 10 is the numerator \n" ); document.write( "then \n" ); document.write( "d = 10 - 4 \n" ); document.write( "d = 6 is the denominator \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Prove this in the statement: \n" ); document.write( "\"the denominator is doubled and the numerator is increased by 6, the sum of \n" ); document.write( "the original fraction and the new one is 3. \n" ); document.write( " \n" ); document.write( " |