document.write( "Question 206227: x= (kyz)/p^2 what % change occurs in x, if y increases by 20%, z decreases by 20% and p is doubled \n" ); document.write( "
| Algebra.Com's Answer #155788 by ptaylor(2198)     You can put this solution on YOUR website! \r \n" ); document.write( "\n" ); document.write( "x= (kyz)/p^2\r \n" ); document.write( "\n" ); document.write( "y increases by 20%=y+0.2y \n" ); document.write( "z decreases by 20%=z-0.2z \n" ); document.write( "p doubles=2p \n" ); document.write( "x1={k(y+0.2y)(z-0.2z)}/(2p)^2 expand (y+0.2y)(z-0.2z) using FOIL \n" ); document.write( "x1=k(yz-0.2yz+0.2yz-0.04yz)/(2p)^2 simplify\r \n" ); document.write( "\n" ); document.write( "x1=(kyz-0.04kyz)/4p^2; \n" ); document.write( "x1=0.96kyz/4p2; \n" ); document.write( "x1=(0.96/4)(kyz/p^2)=(0.96/4)(x) \n" ); document.write( "x1=0.24x \n" ); document.write( "So x decreases by x-0.24x=76%\r \n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |