document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=206066>Question 206066</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi, Im having problems trying to solve these rational equations. its a extraneous solution. Can you help please.\r<BR>\n" );
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document.write( "5/y-3 = y+7/2y-6 + 1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #155780 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=155780\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 5/y-3 = y+7/2y-6 + 1<BR>\n" );
document.write( "5/y-3 = y+7/2(y-3) + 1<BR>\n" );
document.write( "10=y+7+2(y-3) Multiply each side of the equation by 2(y-3) to eliminate fractions.<BR>\n" );
document.write( "y+7+2y-6=10<BR>\n" );
document.write( "3y+1=10<BR>\n" );
document.write( "3y=9<BR>\n" );
document.write( "y=3<BR>\n" );
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document.write( "Now we replace y with 3 in the original equation and find that 5/y-3 becomes 5/3-3=5/0.<BR>\n" );
document.write( "Since division by zero is not allowed then y=3 is an extraneous answer.<BR>\n" );
document.write( "There is no answer.<BR>\n" );
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document.write( "Ed </SPAN>\n" );
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