document.write( "Question 206219: 2x^2+20=-13x \n" ); document.write( "
Algebra.Com's Answer #155777 by anantha(86)\"\" \"About 
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sol:
\n" ); document.write( "solving a Quadratic equation
\n" ); document.write( "step1: write the given Quadratic equation in standard form,ax^2+bx+c=0
\n" ); document.write( "step2: factorize the trinomial ax^2+bx+c and express it as the product of two linear factors
\n" ); document.write( "step3: put each linear factor equal to zero
\n" ); document.write( "thus,two values of x will be obtained,these are the roots of the given quadratic equation.\r
\n" ); document.write( "\n" ); document.write( "sol:\r
\n" ); document.write( "\n" ); document.write( "we have 2x^2+20= -13x
\n" ); document.write( "step1:given equation in standard form is 2x^2+20+13x=0
\n" ); document.write( "here -13x is transpose to L.H.S it convert into +13x
\n" ); document.write( "step2:
\n" ); document.write( "now we find the factors of this quadratic equation
\n" ); document.write( "2x^2+13x+20=0
\n" ); document.write( "now find two numbers with sum=13 and product=(2*20)=40
\n" ); document.write( "clearly,such numbers are 8 and 5,adding these numbers we get 8+5=13 and product we get 8*5=40
\n" ); document.write( "now 2x^2+13x+20=0 can be written as
\n" ); document.write( "2x^2+8x+5x+20=0
\n" ); document.write( "(2x^2+8x)+(5x+20)=0
\n" ); document.write( "2x(x+4)+5(x+4)=0
\n" ); document.write( "(x+4)(2x+5)=0
\n" ); document.write( "step3:
\n" ); document.write( "x+4=0 or 2x+5=0
\n" ); document.write( "x+4=0
\n" ); document.write( "x=-4 ,transpose +4 from L.H.S to R.H.S we get -4
\n" ); document.write( "2x+5=0
\n" ); document.write( "2x= -5
\n" ); document.write( "dividing by 2 on both sides
\n" ); document.write( "2x/2=-5/2
\n" ); document.write( "x= -5/2
\n" ); document.write( "x= -4 or -5/2
\n" ); document.write( "these are the roots of the quadratic equation\r
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