document.write( "Question 206053: given two lines: l1 x+2y=4 and l2 3x-y=5, write the equation of line l such that l is perpendicular to l1, and l has the same y-intercept as l2. \n" ); document.write( "
Algebra.Com's Answer #155776 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( "given two lines: l1 x+2y=4 and l2 3x-y=5, write the equation of line l such that l is perpendicular to l1, and l has the same y-intercept as l2.\r
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\n" ); document.write( "\n" ); document.write( "L1 -----> x + 2y = 4 -----> 2y = -x + 4 \r
\n" ); document.write( "\n" ); document.write( "Therefore, L1, in y = mx + b form is: \"y+=+-%281%2F2%29x+%2B+2\"\r
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\n" ); document.write( "\n" ); document.write( "Therefore, L1's slope is \"-1%2F2\", meaning that its perependicular equation \r
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\n" ); document.write( "\n" ); document.write( "will have a slope of 2.\r
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\n" ); document.write( "\n" ); document.write( "Now, L2 -----> 3x - y = 5 -----> -y = -3x + 5 \r
\n" ); document.write( "\n" ); document.write( "Therefore, L2, in y = mx + b form is: \"y+=+3x+-+5\"\r
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\n" ); document.write( "\n" ); document.write( "Therefore, L2's y-intercept is - 5.\r
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\n" ); document.write( "\n" ); document.write( "Therefore, the equation that is perependicular to x + 2y = 4, and that has the \r
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\n" ); document.write( "\n" ); document.write( "same y-intercept as 3x - y = 5, in y = mx + b form, is: \"highlight_green%28y+=+%0D%0A%0D%0A2x+-+5%29\", and in standard form: \"highlight_green%28-+2x+%2B+y+=+-+5%29\"
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