document.write( "Question 206210: Can you please help me with this problem:\r
\n" ); document.write( "\n" ); document.write( "Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 40 miles per hour and Train B is traveling at 48 miles per hour. Train A passes a station at 11:15PM.. If train B passes the same station at 11:30pm, at what time will train B catch up to train A? (write am, or pm in the answer)
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Algebra.Com's Answer #155764 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 40 miles per hour and Train B is traveling at 48 miles per hour. Train A passes a station at 11:15PM.. If train B passes the same station at 11:30pm, at what time will train B catch up to train A?
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\n" ); document.write( "from the given information, we know that train B is 15 min (.25 hr) behind
\n" ); document.write( " train A, when train A passes the station
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\n" ); document.write( "The distance between the trains at this time: .25 * 48 = 12 mi
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\n" ); document.write( "Let t = time required for train B to catch train A
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\n" ); document.write( "write a distance equation: Dist = speed * time
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\n" ); document.write( "Train B travel dist = Train A travel dist + 12 mi
\n" ); document.write( "48t = 40t + 12
\n" ); document.write( "48t - 40t = 12
\n" ); document.write( "8t = \"12%2F8\"
\n" ); document.write( "t = 1.5 hr or 1 hr 30 min
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\n" ); document.write( "11:15 PM + 1:30 = 00:45 AM, B catches A
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\n" ); document.write( "Check solution by finding the distances (train B travels 12 mi more than train A)
\n" ); document.write( "48 * 1.5 = 72 mi
\n" ); document.write( "40 * 1.5 = 60 mi
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\n" ); document.write( "difference= 12 mi
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