document.write( "Question 28537: a quadrilateral with angles that mesure: 10x-25, 10x, 3x to the second power, and 2x to the second power. solve for x. \n" ); document.write( "
Algebra.Com's Answer #15576 by venugopalramana(3286)\"\" \"About 
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a quadrilateral with angles that mesure: 10x-25, 10x, 3x to the second power, and 2x to the second power. solve for x.
\n" ); document.write( "SUM OF 4 ANGLES IN A QUADRILATERAL =360 DEGREES...SO...
\n" ); document.write( "10X-25+10X+3X^2+2X^2=360
\n" ); document.write( "5X^2+20X-385=0...DIVIDING WITH 5 WE GET...
\n" ); document.write( "X^2+4X-77=0
\n" ); document.write( "X^2+11X-7X-77=0
\n" ); document.write( "X(X+11)-7(X+11)=0
\n" ); document.write( "(X+11)(X-7)=0
\n" ); document.write( "X=7 OR -11..SINCE -11 IS NOT TENABLE X=7\r
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