document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=206197>Question 206197</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how to solve this\r<BR>\n" );
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document.write( "find the equation of the circle describe here..\r<BR>\n" );
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document.write( "{{the circle is tangent to the line 2x-y=3 at the point (2,1) and the center is on the x-axis}}\r<BR>\n" );
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document.write( "tnx. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #155748 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=155748\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> at the point of tangency, the radius of the circle is perpendicular to the tangent line\r<BR>\n" );
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document.write( "perpendicular lines have slopes that are negative reciprocals\r<BR>\n" );
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document.write( "so the slope of a radius is -1/2 ___ it passes through (2,1) ___ and the other end is on the x-axis (y = 0)\r<BR>\n" );
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document.write( "the center of the circle is (4,0) ___ this is down 1 and over 2 from (2,1)\r<BR>\n" );
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document.write( "by Pythagoras, the radius squared is 2^2 + 1^2 ___ so r^2 = 5\r<BR>\n" );
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document.write( "the equation of the circle is ___ (x - 4)^2 + (y - 0)^2 = 5 </SPAN>\n" );
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