document.write( "Question 206194: In 3 years Alex is 3 times older than Kit. A year ago Alex is 7 times older than Kit. How old are they now? \n" ); document.write( "
Algebra.Com's Answer #155738 by Marth(57)\"\" \"About 
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\"In 3 years Alex is 3 times older than Kit.\"
\n" ); document.write( "let x = Kit's age in 3 years
\n" ); document.write( "3x = Alex's age in 3 years
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\n" ); document.write( "\"A year ago Alex is 7 times older than Kit.
\n" ); document.write( "3x-4 = 7(x-4)
\n" ); document.write( "Solve for x.
\n" ); document.write( "\"3x-4=7%28x-4%29\"
\n" ); document.write( "\"3x-4=7x-28\"
\n" ); document.write( "\"24=4x\"
\n" ); document.write( "\"x=6\"
\n" ); document.write( "So x-3 = 3 is Kit's age now, and 3x-3=15 is Alex's age now
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