document.write( "Question 206189: Hi, I really need help on this one problem... I need to solve for \"x\" by taking the square root, and there should be two answers. \"2x%5E2+=+100\"
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Algebra.Com's Answer #155733 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"2x%5E2=100\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2=%28100%29%2F%282%29\" Divide both sides by \"2\".\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2=50\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "\"x=%22%22%2B-sqrt%2850%29\" Take the square root of both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"x=sqrt%2850%29\" or \"x=-sqrt%2850%29\" Break up the \"plus/minus\" to form two equations.\r
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\n" ); document.write( "\n" ); document.write( "\"x=5%2Asqrt%282%29\" or \"x=-5%2Asqrt%282%29\" Simplify the square root.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the solutions are \"x=5%2Asqrt%282%29\" or \"x=-5%2Asqrt%282%29\".
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