document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=206160>Question 206160</A>: <I><SPAN STYLE=\"word-break: break-all;\"> given the sum of two numbers is thirty and that twice the first number is 3 more than the second,find the largest number </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #155720 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=155720\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x & y be the two numbers.<BR>\n" );
document.write( "x+y=30 or x=30-y<BR>\n" );
document.write( "2x=y+3<BR>\n" );
document.write( "2(30-y)=y+3<BR>\n" );
document.write( "60-2y=y+3<BR>\n" );
document.write( "-2y-y=3-60<BR>\n" );
document.write( "-3y=-57<BR>\n" );
document.write( "y=-57/-3<BR>\n" );
document.write( "y=19 ans for the larger number.<BR>\n" );
document.write( "x+19=30<BR>\n" );
document.write( "x=30-19<BR>\n" );
document.write( "x=11 ans for the smaller number.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "2*11=19+3<BR>\n" );
document.write( "22=22<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );