document.write( "Question 206054This question is from textbook Finite Mathematics
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document.write( ": Your company produces two models of bicycles: Model A and Model B. Model A takes 2 hours to assemble, where Model B takes 3 hours to assemble. Model A costs $25 to make per bike where Model B costs $30 to make per bike. If your company has a total of 34 hours and $350 available per day for these two models, how many of each model can be made in a day?
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document.write( "Solve using Elimination Method:
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document.write( "Equation:
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document.write( "120x+180y = 21,600 hours assembling per day
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document.write( "$25x+$30y = $750 costs
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document.write( "first equation:
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document.write( "120x + 180y = 21,600
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document.write( "second equation
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document.write( "(-5) 25 + (-5) 30y = (-5) 750
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document.write( "elimination 245x + 330y = -17,850\r
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document.write( "substitute back in to equation
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document.write( "120x + 180y ( ) = 21,600\r
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document.write( "x = bikes per day\r
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document.write( "I need help solving this equation with the steps
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document.write( "
Algebra.Com's Answer #155718 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Your company produces two models of bicycles: Model A and Model B. \n" ); document.write( "Model A takes 2 hours to assemble, where Model B takes 3 hours to assemble. \n" ); document.write( " Model A costs $25 to make per bike where Model B costs $30 to make per bike. \n" ); document.write( "If your company has a total of 34 hours and $350 available per day for these \n" ); document.write( " two models, how many of each model can be made in a day? \n" ); document.write( "Solve using Elimination Method: \n" ); document.write( ": \n" ); document.write( "I am not sure what you are doing here, but you are making it way more complicated than it is: \n" ); document.write( ": \n" ); document.write( "Let a = no. of A bikes \n" ); document.write( "Let b = no. of B bikes \n" ); document.write( ": \n" ); document.write( "2a + 3b = 34; total hrs available \n" ); document.write( ": \n" ); document.write( "25a + 30b = 350; total cost available \n" ); document.write( "; \n" ); document.write( "Multiply the 1st equation by 10 and subtract from the above equation \n" ); document.write( "25a + 30b = 350 \n" ); document.write( "20a + 30b = 340 \n" ); document.write( "------------------subtraction eliminates b \n" ); document.write( "5a = 10 \n" ); document.write( "a = 2 ea A models \n" ); document.write( ": \n" ); document.write( "use the time equation to find b \n" ); document.write( "2(2) + 3b = 34 \n" ); document.write( "4 + 3b = 34 \n" ); document.write( "3b = 34 - 4 \n" ); document.write( "3b = 30 \n" ); document.write( "b = \n" ); document.write( "b = 10 ea B models per day \n" ); document.write( "; \n" ); document.write( ": \n" ); document.write( "Check solution in the cost equation \n" ); document.write( "25(2) + 30(10) = $350 confirms our solution \n" ); document.write( " |