document.write( "Question 206130: Ruth is twice as old as Pat. In 4 years, Ruth will be three times as old as Pat was 3 years ago. How old is each now? \n" ); document.write( "

Algebra.Com's Answer #155683 by Marth(57) $\"\"$ $\"About$

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Right now, \"Ruth is twice as old as Pat.\"\r
\n" ); document.write( "\n" ); document.write( "let x = Pat's age
\n" ); document.write( "2x = Ruth's age\r
\n" ); document.write( "\n" ); document.write( "\"In 4 years, Ruth will be three times as old as Pat was 3 years ago.\"\r
\n" ); document.write( "\n" ); document.write( " $\"2x%2B4\"$ is Ruth's age in 4 years. $\"x-3\"$ is Pat's age 3 years ago.
\n" ); document.write( "Because Ruth will be three times as old, $\"2x%2B4+=+3%28x-3%29\"$ \r
\n" ); document.write( "\n" ); document.write( "Solve.
\n" ); document.write( " $\"2x%2B4+=+3%28x-3%29\"$
\n" ); document.write( " $\"2x%2B4+=+3x-9\"$
\n" ); document.write( "Subtract $\"2x\"$ and add $\"9\"$ to both sides
\n" ); document.write( " $\"13+=+x\"$
\n" ); document.write( "_______
\n" ); document.write( "Since x = Pat's age and 2x = Ruth's age,
\n" ); document.write( "Pat is 13 now.
\n" ); document.write( "Ruth is 26 now.
\n" ); document.write( " \n" ); document.write( "

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