document.write( "Question 206062: if trains a and b are travelin gthe same direction on parallel tracks. train a is traveling at 100 mph and train b is traveling 120 mph. train a passes a station at 9:20 am if train b passes the same station at 9:32 amd at what time will train b catch up to train A \n" ); document.write( "
Algebra.Com's Answer #155656 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! if trains a and b are traveling the same direction on parallel tracks. \n" ); document.write( " train a is traveling at 100 mph and train b is traveling 120 mph. \n" ); document.write( " train a passes a station at 9:20 am if train b passes the same station at 9:32 \n" ); document.write( " and at what time will train b catch up to train A \n" ); document.write( "; \n" ); document.write( "from the given information, we know that train B is 12 min (.2 hr) behind \n" ); document.write( " train A, when train A passes the station \n" ); document.write( ": \n" ); document.write( "The distance between the trains at this time: .2 * 120 = 24 mi \n" ); document.write( ": \n" ); document.write( "Let t = time required for train B to catch train a \n" ); document.write( ": \n" ); document.write( "write a distance equation: Dist = speed * time \n" ); document.write( ": \n" ); document.write( "Train b travel dist = Train a travel dist + 24 mi \n" ); document.write( "120t = 100t + 24 \n" ); document.write( "120t - 100t = 24 \n" ); document.write( "120t = \n" ); document.write( "t = 1.2 hr or 1 hr 12 min \n" ); document.write( ": \n" ); document.write( "9:20 + 1:12 = 10:32 pm, B catches A \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution by finding the distances (train b travels 24 mi more than train b) \n" ); document.write( "120 * 1.2 = 144 mi \n" ); document.write( "100 * 1.2 = 120 mi \n" ); document.write( "------------------- \n" ); document.write( "difference = 24 mi \n" ); document.write( " \n" ); document.write( " |