document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=206091>Question 206091</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of the ages of a couple is 60. In eight years, husband's age will be five years less than two times the wife's age seven years ago. Find their present ages. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #155647 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=155647\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The sum of the ages of a couple is 60. In eight years, husband's age will be five years less than two times the wife's age seven years ago. Find their present ages.<BR>\n" );
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document.write( "NOW DATA:<BR>\n" );
document.write( "d + m = 60<BR>\n" );
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document.write( "8 yrs. from now DATA:<BR>\n" );
document.write( "(d+8)=2(m-7)-5<BR>\n" );
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document.write( "Simplify the 2nd equation:<BR>\n" );
document.write( "d - 2m = -14-8-5<BR>\n" );
document.write( "d-2m = -27<BR>\n" );
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document.write( "You now have the system:<BR>\n" );
document.write( "d+m = 60<BR>\n" );
document.write( "d-2m=-27<BR>\n" );
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document.write( "Subtract the 2nd from the 1st to solve for \"m\"<BR>\n" );
document.write( "3m = 87<BR>\n" );
document.write( "m = 29 yrs old (the spouse's age NOW)<BR>\n" );
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document.write( "Since d+m = 60 , d = 31 yrs old (the husband's age NOW)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H, </SPAN>\n" );
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