document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=28563>Question 28563</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Write as the logarithm of a single quantity: \r<BR>\n" );
document.write( "\n" );
document.write( "1/4 log(b) 16-2 log(b) 5 + log(b) 7 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #15561 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=15561\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1/4 log(b) 16-2 log(b) 5 + log(b) 7...USING LOG(X^N)=N*LOG(X)<BR>\n" );
document.write( "= {log(b) (16^1/4)}- {log(b) (5^2)} + log(b) 7...USING LOG(XY)=LOG(X)+LOG(Y) AND LOG(X/Y)=LOG(X)-LOG(Y)....AND 2^4=16...AND...5^2=25<BR>\n" );
document.write( "= log(b) {2*7/25)=LOG(B)(14/25) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );