document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=205931>Question 205931</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2.)The denominator of a fraction is 4 less than the numerator. If the denominator is doubled and the numerator is increased by 6, the sum of the original fraction and the new one is 3. Find the original fraction. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #155595 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=155595\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> X/(X-4)+(X+6)/2(X-4)=3<BR>\n" );
document.write( "(2X+X+6)/2(X-4)=3<BR>\n" );
document.write( "(3X+6)/(2X-8)=3<BR>\n" );
document.write( "3(2X-8)=3X+6<BR>\n" );
document.write( "6X-24=3X+6<BR>\n" );
document.write( "6X-3X=6+24<BR>\n" );
document.write( "3X=30<BR>\n" );
document.write( "X=30/3<BR>\n" );
document.write( "X=10 ANS. FOR THE ORIGINAL NUMERATOR.<BR>\n" );
document.write( "(10-4)=6 IS THE ORIGINAL DENOMINATOR.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "10/6+16/2*6=3<BR>\n" );
document.write( "10/6+16/12=3<BR>\n" );
document.write( "20/12+16/12=3<BR>\n" );
document.write( "36/12=3<BR>\n" );
document.write( "3=3 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );