document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=205935>Question 205935</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How can I solve this? pls. help!\r<BR>\n" );
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document.write( "Marie is twelve years older than her brother Ben. Four years from now, Ben will be two-thirds as old as Marie. How old is Ben now? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #155593 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=155593\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let Ben's age be=x & Marie's age be=(x+12)<BR>\n" );
document.write( "In 4 years Ben's age will be (x+4 )<BR>\n" );
document.write( "In 4 years Marie's age will be (x+16)<BR>\n" );
document.write( "So: (x+4)=2/3(x+16)<BR>\n" );
document.write( "(x+4)=(2x+32)/3<BR>\n" );
document.write( "3(x+4)=2x+32<BR>\n" );
document.write( "3x+12=2x+32<BR>\n" );
document.write( "3x-2x=32-12<BR>\n" );
document.write( "x=20 years old is Ben now.<BR>\n" );
document.write( "20+12=32 years old is Marie now.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "20+4=2/3(20+16)<BR>\n" );
document.write( "24=2/3*36<BR>\n" );
document.write( "24=72/3<BR>\n" );
document.write( "24=24 <BR>\n" );
document.write( " </SPAN>\n" );
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