document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=205945>Question 205945</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the perimeter of a standard basketball court is 288 ft. find the dimensions of the basketball court if its length is 44ft. longer than its width. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #155592 by </B><A HREF=/tutors/aboutme.mpl?userid=rfer><B>rfer(16322)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rfer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=155592\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> width=x=50ft<BR>\n" );
document.write( "length=x+44=94ft<BR>\n" );
document.write( "-----------<BR>\n" );
document.write( "p=2w+2L<BR>\n" );
document.write( "2x+2(x+44)=288<BR>\n" );
document.write( "2x+2x+88=288<BR>\n" );
document.write( "4x=200<BR>\n" );
document.write( "x=50 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );