document.write( "Question 205999: A boy swims downstream 0.9 miles in the same amount of time that he can swim 0.6 miles upstream. If the rate of the current is 1.5 mph, how fast can he swim in still water? \n" ); document.write( "
Algebra.Com's Answer #155584 by checkley77(12844)\"\" \"About 
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D=RT OR T=D/R
\n" ); document.write( "T=.9/(R+1.5)
\n" ); document.write( "T=.6/(R-1.5)
\n" ); document.write( ".9/(R+1.5)=.6/(R-1.5)
\n" ); document.write( ".6(R+1.5)=.9(R-1.5)
\n" ); document.write( ".6R+.9=.9R-1.35
\n" ); document.write( ".6R-.9R=-1.35-.9
\n" ); document.write( "-.3R=-2.25
\n" ); document.write( "R=-22.5/-.3
\n" ); document.write( "R=7.5 MPH IS HIS QWIMMING SPEED IN STILL WATER.
\n" ); document.write( "PROOF:
\n" ); document.write( ".9/(7.5+1.5)=.6/(7.5-1.5)
\n" ); document.write( ".9/9=.6/6
\n" ); document.write( ".1=.1
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